eslint/yoda Style
What it does
Require or disallow "Yoda" conditions. This rule aims to enforce consistent style of conditions which compare a variable to a literal value.
Why is this bad?
Yoda conditions are so named because the literal value of the condition comes first while the variable comes second. For example, the following is a Yoda condition:
if ("red" === color) {
}This is called a Yoda condition because it reads as, "if red equals the color", similar to the way the Star Wars character Yoda speaks. Compare to the other way of arranging the operands:
if (color === "red") {
// ...
}This typically reads, "if the color equals red", which is arguably a more natural way to describe the comparison. Proponents of Yoda conditions highlight that it is impossible to mistakenly use = instead of == because you cannot assign to a literal value. Doing so will cause a syntax error and you will be informed of the mistake early on. This practice was therefore very common in early programming where tools were not yet available. Opponents of Yoda conditions point out that tooling has made us better programmers because tools will catch the mistaken use of = instead of == (ESLint will catch this for you). Therefore, they argue, the utility of the pattern doesn't outweigh the readability hit the code takes while using Yoda conditions.
Examples
never
Examples of incorrect code for the default "never" option:
if ("red" === color) {
// ...
}
if (`red` === color) {
// ...
}
if (`red` === `${color}`) {
// ...
}
if (true == flag) {
// ...
}
if (0 <= x && x < 1) {
// ...
}Examples of correct code for the default "never" option:
if (5 & value) {
// ...
}
if (value === "red") {
// ...
}
if (value === `red`) {
// ...
}
if (`${value}` === `red`) {
}exceptRange
Examples of correct code for the "never", { "exceptRange": true } options:
function isReddish(color) {
return color.hue < 60 || 300 < color.hue;
}
if (x < -1 || 1 < x) {
// ...
}
if (count < 10 && 0 <= rand && rand < 1) {
// ...
}
if (`blue` < x && x < `green`) {
// ...
}
function howLong(arr) {
return 0 <= arr.length && arr.length < 10 ? "short" : "long";
}onlyEquality
Examples of correct code for the "never", { "onlyEquality": true } options:
if (x < -1 || 9 < x) {
}
if (x !== "foo" && "bar" != x) {
}
if (x !== `foo` && `bar` != x) {
}always
Examples of incorrect code for the "always" option:
if (color == "blue") {
// ...
}
if (color == `blue`) {
// ...
}Examples of correct code for the "always" option:
if ("blue" == value) {
// ...
}
if (`blue` == value) {
// ...
}
if (`blue` == `${value}`) {
// ...
}
if (-1 < str.indexOf(substr)) {
// ...
}Configuration
The 1st option
type: "never" | "always"
"never"
The default "never" option can have exception options in an object literal, via exceptRange and onlyEquality.
"always"
The "always" option requires that literal values must always come first in comparisons.
The 2nd option
This option is an object with the following properties:
exceptRange
type: boolean
default: false
If the "exceptRange" property is true, the rule allows yoda conditions in range comparisons which are wrapped directly in parentheses, including the parentheses of an if or while condition. A range comparison tests whether a variable is inside or outside the range between two literal values.
onlyEquality
type: boolean
default: false
If the "onlyEquality" property is true, the rule reports yoda conditions only for the equality operators == and ===. The onlyEquality option allows a superset of the exceptions which exceptRange allows, thus both options are not useful together.
How to use
To enable this rule using the config file or in the CLI, you can use:
{
"rules": {
"yoda": "error"
}
}oxlint --deny yoda